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8k^2-16k-280=0
a = 8; b = -16; c = -280;
Δ = b2-4ac
Δ = -162-4·8·(-280)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-96}{2*8}=\frac{-80}{16} =-5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+96}{2*8}=\frac{112}{16} =7 $
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